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Solution: Answer: The electrician needs to cut 13 sixteenths cm of wire.
How much farther did Stefanie swim in the morning than in the evening?
Analysis: To solve this problem, we will subtract two fractions with unlike denominators.
Today we are going to look at some examples of word problems with fractions.
Although they may seem more difficult, in reality, word problems involving fractions are just as easy as those involving whole numbers.
So multiply the first fraction by 3/3 and the second by 7/7.
If you can’t think of the least common denominator, you can always multiply each fraction by the opposite denomination.Example 7: A warehouse has 12 and nine-tenths meters of tape in one area of the building, and eight and three-fifths meters of tape in another part. Analysis: To solve this problem, we will add two mixed numbers, with the fractional parts having unlike denominators.Solution: Answer: The warehouse has 21 and one-half meters of tape in all.For example: 5 – The number of apples (5) corresponds to the numerator (the number which expresses the number of parts that we wish to represent).13 – The total number of fruits (13) corresponds to the denominator (the number which expresses the number of total possible parts).Example 4: Dina added five-sixths of a bag of soil to her garden.Her neighbor Natasha added eleven-eighths bags of soil to her garden. Analysis: To solve this problem, we will subtract two fractions with unlike denominators.Example 6: The Cocozzelli family drove their car for five and five-sixths days to reach their vacation home, and then drove for six and one-sixth days to return home. Analysis: To solve this problem, we will subtract two mixed numbers, with the fractional parts having like denominators.Solution: Answer: The Cocozzelli family took one-half more days to drive home.Sometimes, as in this case, that turns out to be the least common denominator. Once the denominators are matching, subtract the numerators to get 8/21.Example 1: Rachel rode her bike for one-fifth of a mile on Monday and two-fifths of a mile on Tuesday. Analysis: To solve this problem, we will add two fractions with like denominators.