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A weak acid exists in equilibrium so some of the whole acid is being formed at the same time some of the acid is splitting into its ions so there should always be the same amount of ions present.
This applies to bases as well but in this case the ion of interest is OH-.
This is obviously a huge safety concern, particularly if we don’t know what it is.
Handily, if it is an acid or a base there are techniques which can be used to see how strong that chemical is.There is two other questions, but they're very similar, so with the answer to one I think I could work the others out. I'm having some trouble working out how to do these questions as my homework.There is two other questions, but they're very similar, so with the answer to one I think I could work the others out. start by writing out the equation of the neutralisation using Na OH and HCl.Once the burette is filled to the required level (not necessarily right to the top!) and the liquid is settled, you will be familiar with the curved surface of the liquid in the burette, caused by surface tension.It is a long, glass tube with a tap at the end which can be used to very carefully add drops of liquid to a test solution.It has a scale (normally in cubic centimetres) down the side to ensure accurate measurements.The standard is then poured carefully into a burette - be aware that the burette is a tall piece of equipment, so any splashes are more likely to get in your eyes.Remember to clamp the burette very gently so as not the crack the glass.then work out the mol of Na OH with the information given in the question, and then by stoichiometry the mol of HCl that was neutralised. Use this value to work out the concentration of HCL (in cm³ or dm³) by using the equation n=cv Since 1 Mole of Na OH and 1 Mole of HCL reacted that means that 0.0025 moles of HCL reacted, as from our equation (balanced) it's in the ratio 1:1 Remember the formula Moles = concentration x volume?then rearrage mol = vol (in dm^3) x conc to find the concentration of HCl Write a balanced equation. We are going to rearrange to get Concentration = Moles / Volume.